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勋章 ①金银铜:在竞赛中获得第一二三名;②好习惯:自然月10天提交;③里程碑:解决1/2/5/10/20/50/100/200题;④每周打卡挑战:完成每周5题,每年1月1日清零。

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提交日期 题目名称 提交代码
2026-02-04 S1年级物理成绩前10名(2) 
with cx as
(select 
	s.student_id
,s.name
,sc.score
,rank()over(order by sc.score desc) as rk
from students s
inner join scores sc on s.student_id = sc.student_id
where
	s.grade_code ='S1'
and sc.subject = '物理'
 )
select
	student_id
,name
,score
,rk
from cx
where rk<=10
order by
	rk
2026-02-04 S1年级物理成绩前10名(2) 
with cx as
(select 
	s.student_id
,s.name
,sc.score
,rank()over(order by sc.score desc) as rk
from students s
inner join scores sc on s.student_id = sc.student_id
where
	s.grade_code ='S1'
and sc.subject = '物理'
 )
select
	student_id
,name
,score
,rk
from cx
where rk<=10
order by
	rk
limit 10
2026-02-04 S1年级物理成绩前10名(2) 
with cx as
(select 
	s.student_id
,s.name
,sc.score
,rank()over(partition by s.student_id order by sc.score desc) as rk
from students s
inner join scores sc on s.student_id = sc.student_id
where
	s.grade_code ='S1'
and sc.subject = '物理'
 )
select
	student_id
,name
,score
,rk
from cx
where rk<=10
order by
	rk;
2026-02-04 S1年级物理成绩前10名(2) 
select 
	s.student_id
,s.name
,sc.score
,dense_rank()over(partition by s.student_id order by sc.score desc) as rk
from students s,scores sc
where
	s.student_id=sc.student_id
	and s.grade_code ='S1'
and sc.subject = '物理'
order by
	rk,s.student_id
limit 10;
2026-02-04 S1年级物理成绩前10名(1) 
select 
	st.student_id
,st.name
,sc.score
,ROW_NUMBER() OVER (PARTITION BY st.grade_code ORDER BY sc.score DESC) AS rn
from 
	students st
inner join scores sc on st.student_id=sc.student_id
where 
	st.grade_code = 'S1'
and sc.subject = '物理'
order by
	rn,st.student_id
limit 10;
2026-02-04 人数最多的学生姓氏 
select 
	left(name,1) as surname
,count(name) as cnt
from students 
group by 
	surname
order by 
	cnt desc
limit 5;
2026-02-04 人数最多的学生姓氏 
select 
	left(name,1) as surname
,count(student_id) as cnt
from students 
group by 
	surname
order by 
	cnt 
limit 5;
2026-02-04 学生信息和班主任姓名 
select s.name
	,s.class_code
,s.grade_code
,t.name as head_teacher_name
from students s,teachers t
where s.class_code=t.head_teacher
order by s.student_id
2026-02-04 字符串与通配符(1)名称里面有特服,可以使用通配符 
select 
	count(distinct mch_nm) as mch_cnt
from cmb_usr_trx_rcd 
where
	mch_nm like '%按摩保健休闲%'
2026-02-04 分类(1)姿势太多很过分,分类要用CaseWhen 
select
	case 
	when trx_amt = 288 then '1.WithHand'
	when trx_amt = 388 then '2.WithMimi'
 		when trx_amt = 588 then '3.BlowJobbie'
	when trx_amt = 888 then '4.Doi'
when trx_amt = 1288 then '5.DoubleFly' 
	else '6.other' 
end as ser_typ
,count(1) as trx_cnt
,min(date(trx_time)) as first_date
from 
	cmb_usr_trx_rcd 
where
	mch_nm = '红玫瑰按摩保健休闲'
and usr_id = '5201314520'
group by
	ser_typ
order by
	ser_typ
2026-02-04 分组与聚合函数(6)想知道渣男有多坏,疯狂使用GroupBy 
select 
	usr_id
,mch_nm
,sum(trx_amt) as trx_amt
,count(trx_amt) as trx_cnt
,min(trx_time) as first_time
from 
	cmb_usr_trx_rcd 
where
	usr_id = '5201314520'
and trx_amt >= 288
group by
	usr_id,mch_nm
order by
	count(trx_amt) desc
2026-02-04 分组与聚合函数(5)想知道何时成瘾,用Max Or Min? 
select
	usr_id
,min(trx_time) as first_time
,mch_nm
from cmb_usr_trx_rcd
where
	usr_id= '5201314520'
and mch_nm = '红玫瑰按摩保健休闲'
group by
	usr_id
limit 1;
2026-02-04 分组与聚合函数(5)五花八门的项目,其实都有固定套路(2) 
select 
	trx_amt,
count(1) as total_trx_cnt,
count(distinct usr_id) as unique_usr_cnt,
count(1)/count(distinct usr_id) as avg_trx_per_user
from 
	cmb_usr_trx_rcd 
where
left(trx_time, 7) between '2023-01' and '2024-06'
and mch_nm ='红玫瑰按摩保健休闲'
group by
	trx_amt
order by
	avg_trx_per_user desc
limit 5
;
2026-02-04 分组与聚合函数(5)五花八门的项目,其实都有固定套路(2) 
select 
	distinct trx_amt,
count(1) as total_trx_cnt,
count(usr_id) as unique_usr_cnt,
count(1)/count(usr_id) as avg_trx_per_user
from 
	cmb_usr_trx_rcd 
where
	mch_nm ='红玫瑰按摩保健休闲'
and date(trx_time) between '2023-01-01' and '2024-06-30'
group by
	trx_amt
order by
	avg_trx_per_user desc
limit 5
;
2026-02-04 分组与聚合函数(3)五花八门的项目,其实都有固定套路(1) 
select 
trx_amt,
    count(1) as trx_cnt
from 
	cmb_usr_trx_rcd 
where
	mch_nm = '红玫瑰按摩保健休闲'
and date(trx_time) between '2024-01-01' and '2024-07-31'
group by
	trx_amt
order by
	count(trx_amt) desc
limit 5
;
2026-02-04 分组与聚合函数(3)五花八门的项目,其实都有固定套路(1) 
select 
sum(trx_amt) as trx_amt
,count(trx_amt) as trx_cn
from 
	cmb_usr_trx_rcd 
where
	mch_nm = '红玫瑰按摩保健休闲'
and date(trx_time) between '2024-01-01' and '2024-07-31'
group by
	trx_amt
order by
	count(trx_amt) desc
limit 5
;
2026-02-04 分组与聚合函数(3)五花八门的项目,其实都有固定套路(1) 
select 
sum(trx_amt) as trx_amt
,count(trx_amt) as trx_cn
from 
	cmb_usr_trx_rcd 
where
	mch_nm ='红玫瑰按摩保健休闲'
and date(trx_time) between '2024-01-01' and '2024-07-31'
group by
	trx_amt
order by
	count(trx_amt) desc
limit 0,5
;
2026-02-04 分组与聚合函数(2)擦边营收怎么样,聚合函数可看出 
select 
date(trx_time) as dt
	,max(trx_amt) as max_trx_amt
,min(trx_amt) as min_trx_amt
,avg(trx_amt) as avg_trx_amt
,sum(trx_amt) as sum_trx_amt
from 
	cmb_usr_trx_rcd 
where
	year(trx_time) = 2024
and month(trx_time) = 9
and mch_nm = '红玫瑰按摩保健休闲'
group by
	date(trx_time)
order by
	date(trx_time)
;
2026-02-04 分组与聚合函数(2)擦边营收怎么样,聚合函数可看出 
select 
	mch_nm
,date(trx_time) as dt
	,max(trx_amt) as max_trx_amt
,min(trx_amt) as min_trx_amt
,avg(trx_amt) as avg_trx_amt
,sum(trx_amt) as sum_trx_amt
from 
	cmb_usr_trx_rcd 
where
	year(trx_time) = 2024
and month(trx_time) = 9
and mch_nm = '红玫瑰按摩保健休闲'
group by
	date(trx_time)
order by
	date(trx_time)
;
2026-02-04 分组与聚合函数(1)Money全都花在哪,GroupBy来查一查 
select mch_nm
,sum(trx_amt) as sum_trx_amt
from cmb_usr_trx_rcd 
where year(trx_time) = 2024
and usr_id = '5201314520'
group by mch_nm
order by sum_trx_amt desc