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提交日期 题目名称 提交代码
2026-07-20 分组与聚合函数（3）五花八门的项目，其实都有固定套路（1）  
select 
trx_amt,
count(1) as trx_cnt
from cmb_usr_trx_rcd 
where mch_nm = '红玫瑰按摩保健休闲'
and date(trx_time) between '2024-01-01' and '2024-07-31'
group by trx_amt
order by trx_cnt desc
limit 5;
2026-07-20 分组与聚合函数（2）擦边营收怎么样，聚合函数可看出  
select 
date(trx_time) as trx_date,
max(trx_amt),
min(trx_amt),
avg(trx_amt),
sum(trx_amt)
from cmb_usr_trx_rcd
where date(trx_time) between '2024-09-01' and '2024-09-30'
andmch_nm = '红玫瑰按摩保健休闲'
group bydate(trx_time)
order by trx_date;
2026-07-20 分组与聚合函数（1）Money全都花在哪，GroupBy来查一查  
select mch_nm,sum(trx_amt) as sum_trx_amt
from cmb_usr_trx_rcd 
where year(trx_time) = '2024'
and usr_id = '5201314520'
group by mch_nm
;
2026-07-20 条件过滤（3）Hour函数很给力，组合条件要仔细  
select * 
from cmb_usr_trx_rcd 
where usr_id = '5201314520'
and date(trx_time) between '2024-09-01' and '2024-09-30'
and hour(trx_time) in ('22','23','0','1','2','3','4','5')
;
2026-07-20 条件过滤（3）Hour函数很给力，组合条件要仔细  
select * 
from cmb_usr_trx_rcd 
where usr_id = '5201314520'
and date(trx_time) between '2024-09-01' and '2024-09-30'
and hour(trx_time) in ('22','23','0','1','2','3','4','5')
limit 5;
2026-07-20 条件过滤（2）半夜活动有猫腻，Hour函数给给力  
select
    *
from
    cmb_usr_trx_rcd
where
    date(trx_time) 
    between '2024-09-01' and '2024-09-30' 
    and hour(trx_time) between 1 and 5 
    and usr_id = '5201314520' 
order by trx_time
2026-07-20 条件过滤（1）异地男友有异常，数分闺蜜来帮忙  
select
    *
from
    cmb_usr_trx_rcd
where 
    date(trx_time) between '2024-09-01' and '2024-09-30'
    and usr_id='5201314520'
order by 
    trx_time
2026-07-06 红包（一）收发金额统计  
selecttt.user_id,
sum(snd_amt) as total_snd_amt,
sum(rcv_amt) as total_rcv_amt,
sum(rcv_amt) -sum(snd_amt) as net_amt
from (
select 
snd_usr_id as user_id,
sum(pkt_amt) as snd_amt,
0 as rcv_amt
from tx_red_pkt_rcd
group by snd_usr_id
 union all 
 select 
rcv_usr_id as user_id,
0 as snd_amt,
sum(pkt_amt) as rcv_amt
from tx_red_pkt_rcd
	group by rcv_usr_id
) tt
group by tt.user_id
;
2026-07-06 S1年级物理成绩前10名（2）  
with tmp as (
select 
s1.student_id,
s1.name,
s2.score,
rank() over(order by s2.score desc) as rnk
from students s1 join scores s2 
	on s1.student_id = s2.student_id
where s1.grade_code = 'S1'
and s2.subject = '物理'
)
select
student_id,
name,
score,
rnk
from tmp 
where rnk <10
order by rnk;
2026-07-06 S1年级物理成绩前10名（2）  
with tmp as (
select 
s1.student_id,
s1.name,
s2.score,
rank() over(order by s2.score desc) as rnk
from students s1 join scores s2 
	on s1.student_id = s2.student_id
where s1.grade_code = 'S1'
and s2.subject = '物理'
)
select
student_id,
name,
score,
rnk
from tmp 
limit 10
;
2026-07-06 S1年级物理成绩前10名（1）  
with tmp_rank as(
select 
s1.student_id
,s1.name
,s2.score 
,row_number()over(order by s2.score desc) as rnk
from 
	students s1 
join 
	scores s2 on s1.student_id = s2.student_id
	where s1.grade_code = 'S1' 
	and s2.subject= '物理'
)
select 
	t.student_id,
t.name,
t.score,
t.rnk
from tmp_rank t
where t.rnk <=10
order by rnk,student_id;
2026-07-06 S1年级物理成绩前10名（1）  
with tmp_rank as(
select 
s1.student_id
,s1.name
,s2.score 
,row_number()over(order by s2.score desc) as rank_num
from 
	students s1 
join 
	scores s2 on s1.student_id = s2.student_id
	where s1.grade_code = 'S1' 
	and s2.subject= '物理'
)
select 
	t.student_id,
t.name,
t.score,
t.rank_num
from tmp_rank t
where t.rank_num <=10
order by rank_num,student_id;
2026-07-06 S1年级物理成绩前10名（1）  
with tmp_rank as(
select 
s1.student_id
,s1.name
,s2.score 
,row_number()over(order by s2.score desc) as rank_num
from 
	students s1 
join 
	scores s2 on s1.student_id = s2.student_id
	where s1.grade_code = 'S1' 
	and s2.subject= '物理'
)
select 
	t.student_id,
t.name,
t.score,
t.rank_num
from tmp_rank t
where t.rank_num <=10;
2026-07-06 S1年级物理成绩前10名（1）  
with tmp_rank as(
select 
s1.student_id
,s1.name
,s2.score 
,row_number()over(order by s2.score desc) as rank_num
from 
	students s1 
join 
	scores s2 on s1.student_id = s2.student_id
	and s1.grade_code = 'S1' 
	and s2.subject= '物理'
)
select 
	t.student_id,
t.name,
t.score,
t.rank_num
from tmp_rank t
where t.rank_num <=10;
2026-07-06 S1年级物理成绩前10名（1）  
select 
s1.student_id
,s1.name
,s2.score
,row_number()over(order by s2.score desc) as rank_num
from students s1 join scores s2 on s1.student_id = s2.student_id
and s1.grade_code = 'S1' and s2.subject= '物理'
limit 10;
2026-07-06 S1年级物理成绩前10名（1）  
select 
s1.student_id
,s1.name
,s2.score
,row_number()over(order by s2.score desc) as rank_num
from students s1 left join scores s2 on s1.student_id = s2.student_id
and s1.grade_code = 'S1' and s2.subject= '物理'
limit 10;
2026-07-06 人数最多的学生姓氏  
select 
left(s.name,1) as first_name ,count(*) as num
from students s
group by first_name
order by num desc
limit 5;
2026-07-06 人数最多的学生姓氏  
select 
left(s.name,1) as first_name ,count(*) as num
from students s
group by first_name
order by num
limit 5;
2026-07-06 学生信息和班主任姓名  
select 
s.name,s.class_code,s.grade_code,t.name as head_teacher_name
from students s leftjoin teachers t on s.class_code = t.head_teacher
order by s.student_id;
2026-07-06 学生信息和班主任姓名  
select 
s.name,s.class_code,s.grade_code,t.name as head_teacher_name
from students s join teachers t on s.class_code = t.head_teacher
order by s.student_id;