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勋章 ①金银铜:在竞赛中获得第一二三名;②好习惯:自然月10天提交;③里程碑:解决1/2/5/10/20/50/100/200题;④每周打卡挑战:完成每周5题,每年1月1日清零。

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提交日期 题目名称 提交代码
2025-03-04 条件过滤-查找1994年至1997年毕业的女教师 
select name,subject,class_code,graduate_date
from teachers
where year(graduate_date) between 1994 and 1997
and gender='f'
order by graduate_date asc
2025-03-04 条件过滤-符合条件的班主任 
select name,subject,class_code,qualification
from teachers
where head_teacher is not null
and (fir_degr='北京大学' or fir_degr='清华大学')
order by name asc
2025-03-04 条件过滤-找出所有教授数学且具有高级职称的教师 
select t.name,t.subject,t.class_code,t.qualification
from teachers t
where subject='数学' and qualification='Senior'
order by name asc
2025-03-04 表连接(2)渣男去过我对象没去过,那就用LeftJoin 
select a.mch_nm as asshole_tired,a.trx_cnt,b.mch_nm as darling_tired 
from
(selectmch_nm ,count(1)
trx_cnt from cmb_usr_trx_rcd
where year(trx_time) in (2023,2024)
and usr_id='5201314520'
group by mch_nm
having count(*)>=20) a
left join
(select distinct mch_nm
from cmb_usr_trx_rcd
where year(trx_time) in(2023,2024)
and usr_id='5211314521') b
on a.mch_nm=b.mch_nm
 order by 2 desc
2025-03-04 表连接(2)渣男去过我对象没去过,那就用LeftJoin 
select a.mch_nm as asshole_tired,a.trx_cnt,b.mch_nm as darling_tired 
from
(
select mch_nm,count(*) trx_cnt
from cmb_usr_trx_rcd
where usr_id='5201314520'
and year(trx_time) in (2023,2024)
group by mch_nm
having count(*)>=20) a
left join
(select distinct mch_nm
from cmb_usr_trx_rcd
where usr_id='5211314521'
and year(trx_time) in (2023,2024)) b
on a.mch_nm =b.mch_nm 
order by 2 desc
2025-03-04 表连接(2)渣男去过我对象没去过,那就用LeftJoin 
select a.mch_nm as asshole_tired,a.trx_cnt,b.mch_nm as darling_tired 
from
(
select mch_nm,count(*) trx_cnt
from cmb_usr_trx_rcd
where usr_id='5201314520'
and year(trx_time) in (2023,2024)
group by mch_nm
having count(*)>20) a
left join
(select distinct mch_nm
from cmb_usr_trx_rcd
where usr_id='5201314520'
and year(trx_time) in (2023,2024)) b
on a.mch_nm =b.mch_nm 
order by 2 desc
2025-03-04 表连接(1)你们难道都去过?那就试试用InnerJoin 
selecta.*
from 
(select distinct mch_nm from cmb_usr_trx_rcd where usr_id='5201314520' and year(trx_time)=2024) a
join 
(select distinct mch_nm from cmb_usr_trx_rcd where usr_id='5211314521' and year(trx_time)=2024) b 
on a.mch_nm =b.mch_nm
order by 1 desc
2025-03-04 表连接(1)你们难道都去过?那就试试用InnerJoin 
select mch_nm 
from cmb_usr_trx_rcd
where usr_id='5201314520'
or usr_id='5211314521'
and year(trx_time)=2024
group by mch_nm
order by mch_nm desc
2025-03-04 表连接(1)你们难道都去过?那就试试用InnerJoin 
select mch_nm 
from cmb_usr_trx_rcd
where usr_id='5201314520'
and usr_id='5211314521'
and year(trx_time)=2024
group by mch_nm
order by mch_nm desc
2025-03-04 表连接(1)你们难道都去过?那就试试用InnerJoin 
select mch_nm 
from cmb_usr_trx_rcd
where usr_id='5201314520'
and year(trx_time)=2024
group by mch_nm
2025-03-04 分组与聚合函数(5)五花八门的项目,其实都有固定套路(2) 
select trx_amt,
count(1) as total_trx_cnt,
count(distinct(usr_id)) as unique_usr_cnt,
count(1) /count(distinct usr_id) as avg_trx_per_user
 from cmb_usr_trx_rcd
 where mch_nm='红玫瑰按摩保健休闲'
 and ((year(trx_time) =2023and month(trx_time) between 1 and 12)
or (year(trx_time)=2024and month(trx_time) between 1 and 6))
 group by trx_amt
 order by avg_trx_per_user desc
 limit 5
2025-03-04 分组与聚合函数(5)五花八门的项目,其实都有固定套路(2) 
select trx_amt,
count(1) as total_trx_cnt,
count(distinct(usr_id)) as unique_usr_cnt,
count(1) /count(distinct usr_id) as avg_trx_per_user
 from cmb_usr_trx_rcd
 where mch_nm='红玫瑰按摩保健休闲'
 and ((year(trx_time) =2023and month(trx_time) between 1 and 12)
or year(trx_time=2024and month(trx_time) between 1 and 6))
 group by trx_amt
 order by avg_trx_per_user desc
 limit 5
2025-03-04 分组与聚合函数(5)五花八门的项目,其实都有固定套路(2) 
select trx_amt,
count(*) as total_trx_cnt,
count(distinct(usr_id)) as unique_usr_cnt,
count(*) /count(distinct usr_id) as avg_trx_per_user
 from cmb_usr_trx_rcd
 where mch_nm='红玫瑰按摩保健休闲'
 and date(trx_time) between '2023-01-01' and '2023-12-31'
or date(trx_time) between '2024-01-01' and '2023-06-30'
 group by trx_amt
 order by avg_trx_per_user desc
 limit 5
2025-03-04 分组与聚合函数(3)五花八门的项目,其实都有固定套路(1) 
select trx_amt,count(*) as trx_cnt
from cmb_usr_trx_rcd
where mch_nm='红玫瑰按摩保健休闲'
and date(trx_time) between '2024-01-01' and '2024-07-30'
group by trx_amt
order by trx_cnt desc
limit 5
2025-03-04 分组与聚合函数(3)五花八门的项目,其实都有固定套路(1) 
select trx_amt,count(1) as trx_cnt
from cmb_usr_trx_rcd
where mch_nm='红玫瑰按摩保健休闲'
and date(trx_time) between '2024-01-01' and '2024-07-30'
group by trx_amt
order by trx_cnt desc
limit 5
2025-03-04 分组与聚合函数(3)五花八门的项目,其实都有固定套路(1) 
select trx_amt,count(1) as trx_cnt
from cmb_usr_trx_rcd
where mch_nm='红玫瑰按摩保健休闲'
and date(trx_time) between '2024-01-01' and '2024-07-01'
group by trx_amt
order by trx_cnt desc
limit 5
2025-03-04 分组与聚合函数(3)五花八门的项目,其实都有固定套路(1) 
select trx_amt,count(1) as trx_cnt
from cmb_usr_trx_rcd
where mch_nm='红玫瑰按摩保健休闲'
and date(trx_time) between '2024-01-01' and '2024-07-01'
group by trx_amt
order by trx_cnt desc
2025-03-04 分组与聚合函数(2)擦边营收怎么样,聚合函数可看出 
select date(trx_time) as trx_date,
max(trx_amt) as max_trx_amt,
min(trx_amt) as min_trx_amt,
avg(trx_amt) as avg_trx_amt,
sum(trx_amt) as total_trx_amt
from cmb_usr_trx_rcd
where mch_nm='红玫瑰按摩保健休闲'
and date(trx_time) between '2024-09-01' and '2024-09-30'
group by date(trx_time)
order by trx_date
2025-03-04 分组与聚合函数(1)Money全都花在哪,GroupBy来查一查 
select mch_nm,sum(trx_amt) as sum_trx_amt
from cmb_usr_trx_rcd
where year(trx_time)='2024'
and usr_id='5201314520'
group by mch_nm
order by sum_trx_amt desc
2025-03-04 条件过滤(3)Hour函数很给力,组合条件要仔细 
select * 
from cmb_usr_trx_rcd
where date(trx_time) between '2024-09-01' and '2024-09-30'
and (
(hour(trx_time)>=22)
 or 
 (hour(trx_time)between 0 and 5)
)
and usr_id='5201314520'
order by trx_time